A) 0.99 g
B) 0.8 g
C) 1.01 g
D) 0.9 g
Correct Answer: A
Solution :
\[{{g}^{1}}=g\left( 1-\frac{2h}{R} \right)=g\left( 1-\frac{2\times 32}{6400} \right)\]
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