Answer:
\[g=10\text{ }m/{{s}^{2}};\] \[{{g}_{1}}=9\text{ }m/{{s}^{2}};\] \[{{g}_{2}}=?\text{ }h=d\] \[g{{g}_{1}}=\frac{2h}{R}.g\] ????..(1) \[g{{g}_{2}}=\frac{d}{R}.g\] ???..(2) But \[h=d\] \[\frac{g-{{g}_{1}}}{g-{{g}_{2}}}=\frac{2h\times g}{R\times hg}\times R=2\] \[\Rightarrow \]\[g-{{g}_{1}}=2(g-{{g}_{2}})\] \[\Rightarrow \]\[109=2\times 102{{g}_{2}}\] \[\Rightarrow \]\[1=202{{g}_{2}}\]\[\Rightarrow \]\[\text{ }19=2{{g}_{2}}\] \[\Rightarrow \]\[{{g}_{2}}=\frac{19}{2}=9.5\,m/{{s}^{2}}\]
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