Answer:
\[h=ut+\frac{1}{2}{{t}^{2}}\]for ?1? falling body \[{{h}_{1}}=\frac{1}{2}\times 10\times {{2}^{2}}=20m\] \[{{h}_{2}}=\frac{1}{2}\times 10\times 9=45m\] \[{{h}_{2}}{{h}_{1}}=4520=25\text{ }m\]
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