question_answer

The distance moved by a freely falling body (starting from rest) during the\[{{\text{1}}^{\text{st}}}\], \[{{\text{2}}^{\text{nd}}}\] and\[{{\text{3}}^{\text{rd}}}\]... nth second of its motion, are proportional to (a) \[(n-1)\]                        (b) \[(2n-1)\] (c) \[({{n}^{2}}-1)\]                         (d) \[(2n-1)/{{n}^{2}}\]

Answer:

Distance travelled by freely falling body is \[{{1}^{st}},\text{ }{{2}^{nd}},\text{ }{{3}^{rd}}\text{ }....\text{ }{{n}^{th}}\] second of its motion is 1 : 3 : 5 ............... ................. (2n - 1)