Answer:
\[\frac{{{g}_{e}}}{{{g}_{m}}}=?\] \[g=\frac{4}{3}\pi GdR\] \[\Rightarrow \] \[g\propto dR\] (\[\because \]G constant) Earth Moon \[{{R}_{e}}=R\] \[{{R}_{m}}=r\] \[{{d}_{e}}={{\rho }_{e}}\] \[{{d}_{m}}={{\rho }_{m}}\]
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