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JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Gravitation Potential

  • question_answer
     The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth's mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become                             [CBSE PMT 1997]

    A) 5.6 km/s

    B)               11.2 km/s (remain unchanged)

    C)             22.4 km/s

    D)             44.8 km/s

    Correct Answer: C

    Solution :

                    \[{{v}_{e}}=\sqrt{\frac{2GM}{R}}\]\ \[{{v}_{e}}\propto \sqrt{\frac{M}{R}}\] If M becomes double and R becomes half then escape velocity becomes two times.


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