A) mgh
B) \[\frac{4}{5}mgh\]
C) \[\frac{5}{6}mgh\]
D) \[\frac{6}{7}mgh\]
Correct Answer: C
Solution :
\[\Delta U=\frac{mgh}{1+h/R}\] Substituting \[R=5h\] we get \[\Delta U=\frac{mgh}{1+1/5}=\frac{5}{6}mgh\]You need to login to perform this action.
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