A) 1/2 hr
B) 1 hr
C) 2 hrs
D) 4 hrs
Correct Answer: C
Solution :
\[{{T}^{2}}\propto {{R}^{3}};\]with \[{{R}_{e}}=6400\,\,km,\] \[\frac{{{T}^{2}}}{{{(24)}^{2}}}={{\left( \frac{6400}{36000} \right)}^{3}}\Rightarrow T\approx 1.7\,\,hr\] For spy satellite R is slightly greater than Re \[\Rightarrow {{T}_{s}}>T\] \[\therefore {{T}_{s}}=2\,\,hr\]You need to login to perform this action.
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