A) \[\frac{3}{4\pi \rho {{R}_{e}}}\]
B) \[\frac{gR_{e}^{2}}{{{M}_{e}}}\]
C) \[\frac{3g}{4\pi \rho R_{e}^{2}}\]
D) \[\frac{12\rho g}{4\pi {{R}_{e}}}\]
Correct Answer: A
Solution :
\[g=\frac{GM}{{{R}^{2}}},\,\,e=\frac{M}{V}=\frac{M}{\frac{4}{3}\pi R_{e}^{2}},\,\,g=\frac{4}{3}\pi GeR\] \[\Rightarrow G=\frac{gR_{e}^{2}}{{{M}_{e}}},\,G=\frac{3g}{4\pi \rho {{R}_{e}}}\]You need to login to perform this action.
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