A) \[-2\,\,\left( \frac{R}{h} \right)\]
B) \[\frac{R}{h}\]
C) \[\frac{h}{R}\]
D) \[-2\left( \frac{h}{R} \right)\]
Correct Answer: D
Solution :
If \[h<<R,\,\,g=\frac{GM}{{{R}^{2}}}\Rightarrow \frac{dg}{dR}=\frac{2GM}{{{R}^{3}}}\] Given, \[dR=h\,\,\therefore \frac{dg}{h}=\frac{-2GM}{{{R}^{2}}}\times \frac{1}{R}=-\frac{g}{R}\] \[\Rightarrow \frac{dg}{g}=-2\frac{h}{R}\]You need to login to perform this action.
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