Answer:
Total distance = \[2+1+1+\frac{1}{2}+\frac{1}{2}+\frac{1}{4}+\frac{1}{4}=5\frac{1}{2}m=5.5m\] Time between the third and fourth hits is time for moving 0.25 m up and 0.25 m down \[t=2\sqrt{\frac{2h}{g}}=2\sqrt{\frac{2\times \frac{1}{4}}{10}}=\frac{1}{\sqrt{5}}s\]
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