Answer:
Velocity of the stone on reaching the foot of the tower is \[v=\sqrt{{{u}^{2}}+2gh}\Rightarrow 3u=\sqrt{{{u}^{2}}+2gh}\] \[\Rightarrow 9{{u}^{2}}={{u}^{2}}+2gh\Rightarrow h=\frac{4{{u}^{2}}}{g}\]
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