A) 4.8 hours
B) \[48\sqrt{2}\] hours
C) 24 hours
D) \[24\sqrt{2}\] hours
Correct Answer: B
Solution :
First time,\[{{T}^{2}}\propto {{R}^{3}}\] Second time,\[T{{'}^{2}}\propto {{(2R)}^{3}}\] \[\therefore \] \[\frac{T'}{T}=\frac{{{(2R)}^{3/2}}}{{{R}^{3/2}}}={{2}^{3/2}}\] \[\Rightarrow \] \[T'={{2}^{3/2}}T\] (\[\because \,\,T=24\]for genostationary satellite) \[=2\sqrt{2}\times 24=\mathbf{48}\sqrt{\mathbf{2}}\mathbf{hours}\]You need to login to perform this action.
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