A) \[F\propto {{r}^{4}}\]
B) \[F\propto {{r}^{6}}\]
C) \[F\propto {{r}^{2}}\]
D) \[F\propto \frac{1}{{{r}^{2}}}\]
Correct Answer: A
Solution :
Force of attraction, \[F=\frac{G{{\left( \frac{4}{3}\pi {{r}^{3}}d \right)}^{2}}}{{{(2r)}^{2}}}\] where, \[d=\]density of the sphere \[\therefore \] \[F=\frac{4}{9}{{\pi }^{2}}{{d}^{2}}\times {{r}^{4}}\] \[\Rightarrow \] \[F=\alpha \,\,{{r}^{4}}\]You need to login to perform this action.
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