A) \[\text{6}.\text{6 }\times \text{ 1}{{0}^{9}}\text{ joule}\]
B) \[-\text{ 6}.\text{6 }\times \text{ 1}{{0}^{\text{9}}}\text{ joule}\]
C) \[\text{6}.\text{6 }\times \text{ 1}{{0}^{-\text{9}}}\text{ joule}\]
D) \[-\text{ 6}.\text{6 }\times \text{ 1}{{0}^{-\text{9}}}\text{ joule}\]
Correct Answer: B
Solution :
\[K.E.=\frac{G{{M}_{e}}m}{2r}\] \[\therefore \] \[=\frac{(6.67\times {{10}^{-11}})(6.0\times {{10}^{24}})(200)}{2\times (6670\times {{10}^{3}})}\] \[=6.0\times {{10}^{9}}\] joule. Gravitation potential energy, \[U=\frac{G{{M}_{e}}m}{r}=-12.0\times {{10}^{9}}\]joule \[\therefore \]Total energy, \[T=U+K=\mathbf{-6}\mathbf{.6\times 1}{{\mathbf{0}}^{\mathbf{9}}}\]joule.You need to login to perform this action.
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