A) 889N
B) 8.89 N
C) 8889N
D) 88.9 N
Correct Answer: A
Solution :
For earth, \[g=\frac{GM}{{{R}^{2}}}\] For satellite, \[g'=\frac{GM}{{{r}^{2}}}=\frac{g{{R}^{2}}}{{{r}^{2}}}=\frac{g{{R}^{2}}}{{{(3R/2)}^{2}}}\] \[\therefore \] \[g'=\frac{4}{9}g\] \[\Rightarrow \] \[g'=\frac{40}{9}N/kg\] \[\therefore \]Pull on the satellite, \[w=Bg'=200\times \frac{40}{9}=\mathbf{889}\,\,\mathbf{N}\]You need to login to perform this action.
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