A) 30R
B) 15R
C) 6R
D) 5R
Correct Answer: C
Solution :
Let \[m\] be the mass at a distance \[x\] from the centre of the moon where gravitation force is zero. \[\therefore \] \[\frac{G{{M}_{e}}m}{{{(60R-x)}^{2}}}=\frac{G{{M}_{moon}}m}{{{x}^{2}}}\] or \[\frac{81}{{{(60R-x)}^{2}}}=\frac{1}{{{x}^{2}}}\] \[\text{or}\]\[\frac{9}{60-x}=\frac{1}{x}\] or \[x=6R\]You need to login to perform this action.
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