A) 2R
B) \[R/\sqrt{2}\]
C) \[R/2\]
D) \[\sqrt{2}/R\]
Correct Answer: A
Solution :
We know, \[g=\frac{GM}{{{R}^{2}}}\] \[g'=\frac{g}{9}=\frac{GM}{9{{R}^{2}}}\] ?(i) Or \[g'=\frac{GM}{{{(R+h)}^{2}}}\] ?(ii) Equating eqns. (i) and (ii), we get \[9{{R}^{2}}={{(R+h)}^{2}}\] Or \[3R=R+h\] or \[h=3R-R=2R\]You need to login to perform this action.
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