A) The charges on the free plates connected together are destroyed
B) The charges on the free plates are enhanced
C) The energy stored in the system increases
D) The potential difference in the free plates becomes \[2V\]
Correct Answer: D
Solution :
\[{{Q}_{1}}=CV\] and \[{{Q}_{2}}=CV\] Applying charge conservation \[C{{V}_{1}}+C{{V}_{2}}={{Q}_{1}}+{{Q}_{2}}\] \[C{{V}_{1}}+C{{V}_{2}}=2CV\] Þ \[{{V}_{1}}+{{V}_{2}}=2V\]
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