A) 700 Volt
B) 200 Volt
C) 600 Volt
D) 400 Volt
Correct Answer: D
Solution :
Equivalent capacitance \[=\frac{2\times 3}{2+3}=\frac{6}{5}\mu F\] Total charge by \[Q=CV\]\[=\frac{6}{5}\times 1000=1200\mu C\] Potential (V) across \[2\mu F\] is \[V=\frac{Q}{C}=\frac{1200}{2}=600\,volt\] \ Potential on internal plates \[=1000-600=400\,V\]You need to login to perform this action.
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