A) \[\frac{{{C}_{2}}}{{{C}_{1}}+{{C}_{2}}}{{U}_{0}}\]
B) \[\frac{{{C}_{1}}}{{{C}_{1}}+{{C}_{2}}}{{U}_{0}}\]
C) \[\left( \frac{{{C}_{1}}-{{C}_{2}}}{{{C}_{1}}+{{C}_{2}}} \right){{U}_{0}}\]
D) \[\frac{{{C}_{1}}{{C}_{2}}}{2({{C}_{1}}+{{C}_{2}})}{{U}_{0}}\]
Correct Answer: A
Solution :
Loss of energy during sharing =\[\frac{{{C}_{1}}{{C}_{2}}{{({{V}_{1}}-{{V}_{2}})}^{2}}}{2({{C}_{1}}+{{C}_{2}})}\] In the equation, put \[{{V}_{2}}=0,\ {{V}_{1}}={{V}_{0}}\] \ Loss of energy \[=\frac{{{C}_{1}}{{C}_{2}}V_{0}^{2}}{2({{C}_{1}}+{{C}_{2}})}\] \[=\frac{{{C}_{2}}{{U}_{0}}}{{{C}_{1}}+{{C}_{2}}}\] \[\left[ \because \ {{U}_{0}}=\frac{1}{2}{{C}_{1}}V_{0}^{2} \right]\]You need to login to perform this action.
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