A) \[0\mu C\]
B) \[5\mu C\]
C) \[10\mu C\]
D) \[25\mu C\]
Correct Answer: C
Solution :
In steady state condition. No current flows through line (1). Hence total current \[i=\frac{2.5}{(1+1+0.5)}=1\,A\] Potential difference a cross line (2) = potential difference a cross capacitor \[=1\times 2=2\,Volt\] So, charge on capacitor = 5 ´ 2 = 10 mCYou need to login to perform this action.
You will be redirected in
3 sec