A) \[\frac{400}{9}\text{V}\]
B) \[\frac{800}{9}V\]
C) \[400\ V\]
D) \[200\,V\]
Correct Answer: B
Solution :
Initially potential difference a cross each capacitor \[{{V}_{1}}=\frac{20}{(10+20)}\times 200=\frac{400}{3}V\] and \[{{V}_{2}}=\frac{10}{(10+20)}\times 200=\frac{200}{3}V\] Finally common potential \[V=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\] \[V=\frac{10\times \frac{400}{3}+20\times \frac{200}{3}}{(10+20)}=\frac{800}{9}V\]You need to login to perform this action.
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