A) \[Q,\,2Q\]
B) \[Q/3,\,2Q/3\]
C) \[3Q/2,\,3Q\]
D) \[2Q/3,\,4Q/3\]
Correct Answer: B
Solution :
In steady state charge on C1 is \[{{Q}_{1}}=\left( \frac{{{C}_{1}}}{{{C}_{1}}+{{C}_{2}}} \right)\times Q=\frac{Q}{3}\] and charge on C2 is \[{{Q}_{2}}=\left( \frac{{{C}_{2}}}{{{C}_{1}}+{{C}_{2}}} \right).Q=\frac{2}{3}Q\]You need to login to perform this action.
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