JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    Two capacitors of 1mF  and 2mF  are connected in series, the resultant capacitance will be                             [MP PET 2002]

    A)            \[4\mu \,F\]                         

    B)            \[\frac{2}{3}\mu \,F\]

    C)            \[\frac{3}{2}\mu \,F\]      

    D)            \[3\mu \,F\]

    Correct Answer: B

    Solution :

               \[\frac{1}{{{C}_{eq}}}=\frac{1}{1}+\frac{1}{2}\Rightarrow {{C}_{eq}}=\frac{2}{3}\mu F\]


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