question_answer

Three capacitors each of capacity \[4\mu \,F\] are to be connected in such a way that the effective capacitance is \[6\,\mu \,F\]. This can be done by                                                                         [CBSE PMT 2003]

A)            Connecting them in parallel

B)            Connecting two in series and one in parallel

C)            Connecting two in parallel and one in series

D)            Connecting all of them in series

Correct Answer: B

Solution :

                   The given circuit can be drawn as follows Þ CAB = 2+4 = 6mF