A) \[9\,\mu \,F\], \[1\,\mu \,F\]
B) \[8\,\mu \,F\], \[2\,\mu \,F\]
C) \[9\,\mu \,F\], \[0\,\mu \,F\]
D) \[3\,\mu \,F\], \[2\,\mu \,F\]
Correct Answer: A
Solution :
\[{{C}_{\max }}=nC=3\times 3=9\mu F\], \[{{C}_{\min }}=\frac{C}{n}=\frac{3}{3}=1\,\mu F\]
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