JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    A capacitor of capacity \[{{C}_{1}}\]is charged upto V volt and then connected to an uncharged capacitor of capacity \[{{C}_{2}}\]. Then final potential difference across each will be  [MP PET 2000; CBSE PMT 2002; MP PET 2003]

    A)            \[\frac{{{C}_{2}}V}{{{C}_{1}}+{{C}_{2}}}\]

    B)                                      \[\left( 1+\frac{{{C}_{2}}}{{{C}_{1}}} \right)\,V\]

    C)            \[\frac{{{C}_{1}}V}{{{C}_{1}}+{{C}_{2}}}\]                   

    D)            \[\left( 1-\frac{{{C}_{2}}}{{{C}_{1}}} \right)\,V\]

    Correct Answer: C

    Solution :

               Common potential  \[{V}'=\frac{{{C}_{1}}V+{{C}_{2}}\times 0}{{{C}_{1}}+{{C}_{2}}}=\frac{{{C}_{1}}}{{{C}_{1}}+{{C}_{2}}}.V\]


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