question_answer

All six capacitors shown are identical, Each can withstand maximum 200 volts between its terminals. The maximum voltage that can be safely applied between A and B is [MP PMT 2004]

A)                    1200 V

B)                    400 V

C)                    800 V

D)                    200 V

Correct Answer: B

Solution :

                   Given circuit can be reduced as follows (C = capacitance of each capacitor) The capacitor 3C, 3C shown in figure can with stand maximum 200 V. \ So maximum voltage that can be applied across A and B equally shared. Hence maximum voltage applied cross A and B be equally shared. Hence max. voltage applied across A and B will be (200 + 200) = 400 volt.