A) \[\frac{1}{2}\mu F\]
B) 1 mF
C) 2 mF
D) 3 mF
Correct Answer: B
Solution :
\[\frac{1}{{{C}_{eq}}}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}\]\[=\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\] \[=\frac{3+2+1}{6}=\frac{6}{6}=1\mu F\]
You need to login to perform this action.
You will be redirected in
3 sec
