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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    Three capacitors of capacitance 1 mF, 2 mF and 3 mF are connected in series and a potential difference of 11 V is applied across the combination. Then, the potential difference across the plates of 1 mF capacitor is        [DCE 2003]

    A)                    2 V

    B)                                      4 V

    C)                    1 V                                    

    D)            6 V

    Correct Answer: D

    Solution :

                       Equivalent capacitance \[\frac{1}{{{C}_{eq}}}=\frac{1}{1}+\frac{1}{2}+\frac{1}{3}\] Þ \[{{C}_{eq}}=\frac{6}{11}\mu F\] Charge supplied from battery \[Q=\frac{6}{11}\times 11=6\mu C\] Hence potential difference across 1mF capacitor \[=\frac{6}{1}=6V\]


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