A) 167 V
B) 100 V
C) 625 V
D) 250 V
Correct Answer: C
Solution :
After charging, total charge on the capacitor Q = CV \[=\text{1}0\times \text{1}{{0}^{\text{6}}}F\times \text{1}000V=\text{1}{{0}^{\text{2}}}C\]. Common potential \[V=\frac{{{C}_{1}}{{V}_{1}}}{{{C}_{1}}+{{C}_{2}}}\]\[=\frac{{{10}^{-2}}}{16\times {{10}^{-6}}}\]= 625V.
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