A) \[{{Q}_{1}}={{Q}_{2}}={{Q}_{3}}\] and \[{{V}_{1}}={{V}_{2}}={{V}_{3}}=V\]
B) \[{{Q}_{1}}={{Q}_{2}}+{{Q}_{3}}\]and\[V={{V}_{1}}+{{V}_{2}}+{{V}_{3}}\]
C) \[{{Q}_{1}}={{Q}_{2}}+{{Q}_{3}}\] and \[V={{V}_{1}}+{{V}_{2}}\]
D) \[{{Q}_{2}}={{Q}_{3}}\] and \[{{V}_{2}}={{V}_{3}}\]
Correct Answer: C
Solution :
\[{{Q}_{1}}={{Q}_{2}}+{{Q}_{3}}\] because in series combination charge is same on both the condenser and \[V={{V}_{1}}+{{V}_{2}}\] because in parallel combination \[{{V}_{2}}={{V}_{3}}.\] Hence \[V={{V}_{1}}+{{V}_{2}}\]You need to login to perform this action.
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