question_answer

. In the circuit diagram shown in the adjoining figure, the resultant capacitance between P and Q is                                                                                   [MP PET/PMT 1988]           

A)            \[47\mu F\]

B)                    \[3\mu F\]

C)                    \[60\mu F\]

D)                    \[10\mu F\]

Correct Answer: B

Solution :

                   The given circuit can be drawn as where \[C=(3+2)\mu F=5\mu F\] \[\frac{1}{{{C}_{PQ}}}=\frac{1}{5}+\frac{1}{20}+\frac{1}{12}=\frac{20}{60}=\frac{1}{3}\]  Þ \[{{C}_{PQ}}=3\mu F\]