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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    The capacitor of capacitance \[4\mu F\] and\[6\mu F\] are connected in series. A potential difference of \[500\ volts\] is applied to the outer plates of the two capacitor system. The potential difference across the plates of capacitor of \[4\mu F\] capacitance is

    A)                    \[500\ volts\]

    B)                                      \[300\ volts\]

    C)                    \[200\ volts\]               

    D)            \[250\ volts\]

    Correct Answer: B

    Solution :

               Potential difference across 4mF capacitor \[V=\left( \frac{6}{4+6} \right)\times 500=300\,volt\]


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