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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    A capacitor of capacity \[{{C}_{1}}\]is charged to the potential of \[{{V}_{o}}\]. On disconnecting with the battery, it is connected with a capacitor of capacity \[{{C}_{2}}\] as shown in the adjoining figure. The ratio of energies before and after the connection of switch \[S\] will be

    A)            \[({{C}_{1}}+{{C}_{2}})/{{C}_{1}}\]

    B)                    \[{{C}_{1}}/({{C}_{1}}+{{C}_{2}})\]

    C)                    \[{{C}_{1}}{{C}_{2}}\]

    D)                    \[{{C}_{1}}/{{C}_{2}}\]

    Correct Answer: A

    Solution :

                       Energy (U) \[=\frac{{{q}^{2}}}{2C}\].  q remains same so \[U\propto \frac{1}{C}\] Þ  \[\frac{{{U}_{Before}}}{{{U}_{After}}}=\]\[\frac{{{C}_{1}}+{{C}_{2}}}{{{C}_{1}}}\]


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