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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    Two condensers of capacities \[1\mu F\] and\[2\mu F\] are connected in series and the system is charged to\[120\ volts\]. Then the P.D. on \[1\mu F\] capacitor (in volts) will be    [MP PMT 1987]

    A)                    40                                      

    B)            60

    C)                    80

    D)            120

    Correct Answer: C

    Solution :

               Charges developed are same so \[{{C}_{1}}{{V}_{1}}={{C}_{2}}{{V}_{2}}\] Þ \[\frac{{{V}_{1}}}{{{V}_{2}}}=2\] \[{{V}_{1}}+{{V}_{2}}=120\] Þ \[{{V}_{1}}=80\,volts\]     


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