question_answer

The capacities and connection of five capacitors are shown in the adjoining figure. The potential difference between the points \[A\] and \[B\] is \[60\ volts\]. Then the equivalent capacity between \[A\] and \[B\] and the charge on \[5\mu F\] capacitance will be respectively

A)            \[44\mu F;\ 300\mu C\]

B)                    \[16\mu F;\ 150\mu C\]

C)                    \[15\mu F;\ 200\mu C\]

D)                    \[4\mu F;\ 50\mu C\]

Correct Answer: D

Solution :

           The given circuit can be redrawn ass follows Equivalent capacitance of the circuit \[{{C}_{AB}}=4\mu F\] Charge given by the battery \[Q={{C}_{eq}}V=4\times 60=240\mu C\] Charge in 5mF capacitor \[Q'=\frac{5}{(10+5+9)}\times 240=50\mu C\]