JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    Four plates of the same area of cross-section are joined as shown in the figure. The distance between each plate is\[d\]. The equivalent capacity across A and B will be

    A)            \[\frac{2{{\varepsilon }_{0}}A}{d}\]

    B)                    \[\frac{3{{\varepsilon }_{0}}A}{d}\]

    C)                    \[\frac{3{{\varepsilon }_{0}}A}{2d}\]

    D)                    \[\frac{{{\varepsilon }_{0}}A}{d}\]

    Correct Answer: B

    Solution :

     The given arrangement is equivalent to the parallel combination of three identical capacitors. Hence equivalent capacitance \[=3C=3\frac{{{\varepsilon }_{0}}A}{d}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner