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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    In the adjoining figure, four capacitors are shown with their respective capacities and the P.D. applied. The charge and the P.D. across the \[4\mu F\] capacitor will be

    A)            \[600\mu C;\ 150\ volts\]

    B)                    \[300\mu C;\ 75\ volts\]

    C)                    \[800\mu C;\ 200\ volts\]

    D)                    \[580\mu C;\ 145\ volts\]

    Correct Answer: D

    Solution :

                       Total capacitance \[\frac{1}{C}=\frac{1}{20}+\frac{1}{8}+\frac{1}{12}\] Þ \[C=\frac{120}{31}\mu F\] Total charge \[Q=CV=\frac{120}{31}\times 300=1161\mu C\] Charge, through 4 mF condenser \[=\frac{1161}{2}=580\mu C\] and potential difference across it \[=\frac{580}{4}=145V\]


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