A) \[22\times {{10}^{-6}}\,J\]
B) \[11\times {{10}^{-6}}\,J\]
C) \[\left( \frac{32}{3} \right)\times {{10}^{-6}}\,J\]
D) \[\left( \frac{16}{3} \right)\times {{10}^{-6}}\,J\]
Correct Answer: B
Solution :
\[{{C}_{eq}}=\frac{{{C}_{1}}{{C}_{2}}}{{{C}_{1}}+{{C}_{2}}}+{{C}_{3}}=\frac{2\times 6}{2+6}+4=5.5\,\mu \,F\] Energy supplied \[(E)=QV=C{{V}^{2}}=22\times {{10}^{-6}}\,J\] P.E. stored\[(U)=\frac{1}{2}{{C}_{eq}}{{V}^{2}}=\frac{1}{2}\times 5.5\times {{(2)}^{2}}=11\times {{10}^{-6}}J\] Þ Energy lost\[=E-U=11\times {{10}^{-6}}\,J\]You need to login to perform this action.
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