A) 12
B) 24
C) 36
D) 32
Correct Answer: B
Solution :
Equivalent capacity between A and B \[=\frac{6\times 4}{10}=2.4\,\mu F\] Hence charge across 4mF (Since in series combination charge remains constant) or \[\text{6}\mu F=\text{ 2}.\text{4}\times \text{1}0\text{ }=\text{ 24}\mu C\]You need to login to perform this action.
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