question_answer

What is the equivalent capacitance between \[A\]and\[B\] in the given figure (all are in farad)                                   [BHU 1997]

A)            \[\frac{13}{18}F\]

B)                    \[\frac{48}{13}F\]

C)                    \[\frac{1}{31}F\]

D)                    \[\frac{240}{71}F\]

Correct Answer: D

Solution :

                   The given circuit can be simplified as follows Hence equivalent capacitance between A and B \[\frac{1}{{{C}_{AB}}}=\frac{1}{12}+\frac{1}{20/3}+\frac{1}{16}\] Þ \[{{C}_{AB}}=\frac{240}{71}F\]