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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    A condenser having a capacity of 6mF is charged to 100 V and is then joined to an uncharged condenser of \[14\mu F\] and then removed. The ratio of the charges on 6mF  and 14mF  and the potential of 6mF will be                   [MP PMT 1991]

    A)                    \[\frac{6}{14}\] and \[50\ volt\]

    B)                                      \[\frac{14}{6}\] and \[30\ volt\]

    C)                    \[\frac{6}{14}\] and \[30\ volt\]                               

    D)            \[\frac{14}{6}\] and 0\[volt\]

    Correct Answer: C

    Solution :

                       Let \[{{q}_{1}},\,{{q}_{2}}\] be the charges on two condensers                    \ \[V=\frac{{{q}_{1}}}{6}=\frac{{{q}_{2}}}{14}\] Þ \[\frac{{{q}_{1}}}{{{q}_{2}}}=\frac{6}{14}=\frac{3}{7}\]                    Also \[{{q}_{1}}+{{q}_{2}}=600\]Þ \[{{q}_{1}}+\frac{14}{6}{{q}_{1}}=600\]Þ \[{{q}_{1}}=\frac{600}{20}\times 6\]                    \ \[V=\frac{{{q}_{1}}}{6}=\frac{600}{20}=30\,volt\]


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