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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    \[0.2F\]capacitor is charged to \[600\,V\]by a battery. On removing the battery, it is connected with another parallel plate condenser of 1F. The potential decreases to                                                                         [MNR 1978; MP PET 2002]

    A)                                                      \[100\ volts\]

    B)                                      \[120\ volts\]

    C)                    \[300\ volts\]               

    D)            \[600\ volts\]

    Correct Answer: A

    Solution :

               By using charge conservation \[0.2\times 600=(0.2+1)V\]                    Þ \[V=\frac{0.2\times 600}{1.2}=100\,V\]         


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