question_answer

In the circuit shown in the figure, the potential difference across the 4.5mF capacitor is                                                        [MP PET 1992; RPET 2001; BVP 2003]

A)                    \[\frac{8}{3}\ volts\]

B)                    4 \[volts\]

C)                    6\[volts\]

D)                    8 \[volts\]

Correct Answer: D

Solution :

                   The given circuit can be redrawn as follows potential difference across 4.5 mF capacitor V\[=\frac{9}{\left( \frac{9}{2}+9 \right)}\times 12\] =  8 V