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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Grouping of Capacitors

  • question_answer
    The equivalent capacitance between \[A\] and \[B\] in the figure is\[1\mu F\]. Then the value of capacitance \[C\] is                   [MP PET 1994]

    A)                    \[1.4\mu F\]

    B)                    \[2.5\mu F\]

    C)                    \[3.5\mu F\]

    D)                    \[1.2\mu F\]

    Correct Answer: A

    Solution :

                       From the given figure, total capacitance is                    \[\frac{1}{1}=\frac{1}{C}+\frac{1}{(1+2.5)}\] Þ \[1=\frac{1}{C}+\frac{1}{3.5}\]Þ \[C=\frac{3.5}{2.5}=1.4\,\mu F\]


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