A) \[10\mu F\]
B) \[20\mu F\]
C) \[30\mu F\]
D) \[15\mu F\]
Correct Answer: D
Solution :
\[V=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\] Þ \[20=\frac{10\times 50+{{C}_{2}}\times 0}{10+{{C}_{2}}}\] Þ \[200+20{{C}_{2}}=500\] Þ \[{{C}_{2}}=15\,\mu F\]
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