A) \[\frac{2{{\varepsilon }_{0}}A}{d}\]
B) \[\frac{3{{\varepsilon }_{0}}A}{d}\]
C) \[\frac{3{{\varepsilon }_{0}}A}{d}\]
D) \[\frac{{{\varepsilon }_{0}}A}{d}\]
Correct Answer: A
Solution :
The given circuit is equivalent to a parallel combination two identical capacitors Hence equivalent capacitance between A and B is C = \[\frac{{{\varepsilon }_{0}}A}{d}+\frac{{{\varepsilon }_{0}}A}{d}\] \[=\frac{2{{\varepsilon }_{0}}A}{d}\]You need to login to perform this action.
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