A) \[\frac{1}{2}\]
B) 2
C) \[\frac{1}{4}\]
D) 4
Correct Answer: B
Solution :
In series combination Q is constant, hence according to \[U=\frac{{{Q}^{2}}}{2C}\] Þ \[U\propto \frac{1}{C}\] Þ \[\frac{{{U}_{1}}}{{{U}_{2}}}=\frac{{{C}_{2}}}{{{C}_{1}}}=\frac{0.6}{0.3}=\frac{2}{1}\]You need to login to perform this action.
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